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Factor.\newline5t2+12t+45t^2 + 12t + 4

Full solution

Q. Factor.\newline5t2+12t+45t^2 + 12t + 4
  1. Identify aa, bb, cc: Identify aa, bb, and cc in the quadratic expression 5t2+12t+45t^2 + 12t + 4 by comparing it with the standard form ax2+bx+cax^2 + bx + c.
    a=5a = 5
    b=12b = 12
    bb00
  2. Find two numbers: Find two numbers that multiply to aca*c (which is 54=205*4=20) and add up to bb (which is 1212).\newlineThe two numbers that satisfy these conditions are 1010 and 22 because 102=2010*2=20 and 10+2=1210+2=12.
  3. Rewrite middle term: Rewrite the middle term, 12t12t, using the two numbers found in the previous step.\newline5t2+12t+45t^2 + 12t + 4 can be rewritten as 5t2+10t+2t+45t^2 + 10t + 2t + 4.
  4. Group terms for factoring: Group the terms into two pairs to factor by grouping.\newline(5t2+10t)+(2t+4)(5t^2 + 10t) + (2t + 4)
  5. Factor out common factor: Factor out the greatest common factor from each pair. 5t(t+2)+2(t+2)5t(t + 2) + 2(t + 2)
  6. Factor out (t+2)(t + 2): Since (t+2)(t + 2) is a common factor in both groups, factor it out.(5t+10)(t+2)(5t + 10)(t + 2) is the factored form of the quadratic expression.