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Factor.\newline4r2+20r+254r^2 + 20r + 25

Full solution

Q. Factor.\newline4r2+20r+254r^2 + 20r + 25
  1. Identify Form: Identify the form of the quadratic trinomial.\newlineThe given expression 4r2+20r+254r^2 + 20r + 25 is a quadratic trinomial in the form of ar2+br+car^2 + br + c.
  2. Find Common Factor: Look for a common factor in all three terms. In this case, there is no common factor other than 11, so we proceed to factor by grouping or by using the perfect square trinomial formula.
  3. Recognize Pattern: Recognize the pattern of a perfect square trinomial.\newlineA perfect square trinomial is in the form a2+2ab+b2a^2 + 2ab + b^2, which can be factored into (a+b)2(a + b)^2. We need to check if 4r2+20r+254r^2 + 20r + 25 fits this pattern.
  4. Rewrite 4r24r^2: Rewrite 4r24r^2 in the form of a2a^2. 4r24r^2 can be written as (2r)2(2r)^2, which suggests that a=2ra = 2r.
  5. Rewrite 2525: Rewrite 2525 in the form of b2b^2.\newline2525 can be written as 525^2, which suggests that b=5b = 5.
  6. Check Middle Term: Check if the middle term fits the pattern 2ab2ab. For the expression to be a perfect square trinomial, the middle term should be 2×a×b2 \times a \times b. Let's check: 2×(2r)×5=20r2 \times (2r) \times 5 = 20r, which matches the middle term of the given expression.
  7. Write Factored Form: Write the factored form of the expression 4r2+20r+254r^2 + 20r + 25. Since we have confirmed that the expression is a perfect square trinomial, we can write it as (a+b)2(a + b)^2. Therefore, the factored form is (2r+5)2(2r + 5)^2.