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Factor.\newline4k2+7k+34k^2 + 7k + 3

Full solution

Q. Factor.\newline4k2+7k+34k^2 + 7k + 3
  1. Identify aa, bb, cc: Identify aa, bb, and cc in the quadratic expression 4k2+7k+34k^2 + 7k + 3 by comparing it with the standard form ax2+bx+cax^2 + bx + c.
    a=4a = 4
    b=7b = 7
    bb00
  2. Find two numbers: Find two numbers that multiply to aca*c (which is 43=124*3=12) and add up to bb (which is 77).\newlineThe two numbers that satisfy these conditions are 44 and 33 because:\newline43=124 * 3 = 12\newline4+3=74 + 3 = 7
  3. Rewrite middle term: Rewrite the middle term, 7k7k, using the two numbers found in the previous step.\newline4k2+7k+34k^2 + 7k + 3 can be expressed as 4k2+4k+3k+34k^2 + 4k + 3k + 3.
  4. Factor by grouping: Factor by grouping. Group the first two terms together and the last two terms together.\newline(4k2+4k)+(3k+3)(4k^2 + 4k) + (3k + 3)
  5. Factor out common factor: Factor out the common factor from each group.\newline4k(k+1)+3(k+1)4k(k + 1) + 3(k + 1)
  6. Factor out common factor: Since both groups contain the common factor (k+1)(k + 1), factor this out.(4k+3)(k+1)(4k + 3)(k + 1)