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Factor.\newline3w2+11w+63w^2 + 11w + 6

Full solution

Q. Factor.\newline3w2+11w+63w^2 + 11w + 6
  1. Identify coefficients: Identify the coefficients aa, bb, and cc in the quadratic expression 3w2+11w+63w^2 + 11w + 6 by comparing it to the standard form ax2+bx+cax^2 + bx + c.a=3a = 3b=11b = 11c=6c = 6
  2. Find two numbers: Find two numbers that multiply to aca*c (36=183*6 = 18) and add up to bb (1111).\newlineThe two numbers that satisfy these conditions are 22 and 99 because 29=182*9 = 18 and 2+9=112+9 = 11.
  3. Rewrite middle term: Rewrite the middle term 11w11w using the two numbers found in the previous step.\newline3w2+11w+63w^2 + 11w + 6 can be rewritten as 3w2+2w+9w+63w^2 + 2w + 9w + 6.
  4. Group and factor: Group the terms into two pairs and factor by grouping.\newlineGroup (3w2+2w)(3w^2 + 2w) and (9w+6)(9w + 6).\newlineFactor out the greatest common factor from each group.\newlineFrom (3w2+2w)(3w^2 + 2w), factor out ww: w(3w+2)w(3w + 2).\newlineFrom (9w+6)(9w + 6), factor out 33: 3(3w+2)3(3w + 2).
  5. Notice common factor: Notice that both groups now contain the common factor 3w+23w + 2. Write the expression as the product of this common factor and the other factors. The factored form is w+3)(3w+2w + 3)(3w + 2.