Factor. 3s^3 + s^2 - 18s - 6 ______

Group Terms: Group the terms to find common factors. We can group the terms as follows: (3s^3 + s^2) and (-18s - 6).Factor Common Factors: Factor out the greatest common factor from each group. From the first group (3s^3 + s^2), we can factor out s^2, giving us s^2(3s + 1). From the second group (-18s - 6), we can factor out -6, giving us -6(3s + 1).Write Factored Form: Write the factored form of the polynomial. We found: 3s^3 + s^2 = s^2(3s + 1) -18s - 6 = -6(3s + 1) Now, we can factor out (3s + 1) from both terms. So, the factored form of 3s^3 + s^2 - 18s - 6 is (s^2 - 6)(3s + 1).

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Factor. $\newline$ $3s^3 + s^2 - 18s - 6$

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Q. Factor.

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3s^3 + s^2 - 18s - 6

Group Terms: Group the terms to find common factors. $\newline$ We can group the terms as follows: $3s^3 + s^2$ and $-18s - 6$ .
Factor Common Factors: Factor out the greatest common factor from each group. $\newline$ From the first group $3s^3 + s^2$ , we can factor out $s^2$ , giving us $s^2(3s + 1)$ . $\newline$ From the second group $-18s - 6$ , we can factor out $-6$ , giving us $-6(3s + 1)$ .
Write Factored Form: Write the factored form of the polynomial. $\newline$ We found: $\newline$ $3s^3 + s^2 = s^2(3s + 1)$ $\newline$ $-18s - 6 = -6(3s + 1)$ $\newline$ Now, we can factor out $(3s + 1)$ from both terms. $\newline$ So, the factored form of $3s^3 + s^2 - 18s - 6$ is $(s^2 - 6)(3s + 1)$ .