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Factor.\newline3n2+11n+63n^2 + 11n + 6

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Q. Factor.\newline3n2+11n+63n^2 + 11n + 6
  1. Identify aa, bb, cc: Identify aa, bb, and cc in the quadratic expression 3n2+11n+63n^2 + 11n + 6. Compare 3n2+11n+63n^2 + 11n + 6 with the standard form ax2+bx+cax^2 + bx + c. a=3a = 3 bb00 bb11
  2. Find Numbers Multiply Add: Find two numbers that multiply to aca*c (which is 36=183*6=18) and add up to bb (which is 1111).\newlineThe two numbers that satisfy these conditions are 22 and 99 because 29=182*9 = 18 and 2+9=112+9 = 11.
  3. Rewrite Middle Term: Rewrite the middle term 11n11n using the two numbers found in Step 22.\newline3n2+11n+63n^2 + 11n + 6 can be rewritten as 3n2+2n+9n+63n^2 + 2n + 9n + 6.
  4. Factor by Grouping: Factor by grouping.\newlineGroup the terms into two pairs: (3n2+2n)(3n^2 + 2n) and (9n+6)(9n + 6).\newlineFactor out the greatest common factor from each pair.\newlineFrom 3n2+2n3n^2 + 2n, factor out nn to get n(3n+2)n(3n + 2).\newlineFrom 9n+69n + 6, factor out 33 to get 3(3n+2)3(3n + 2).
  5. Write Factored Form: Write the factored form of the expression.\newlineSince both groups contain the factor (3n+2)(3n + 2), factor this out to get:\newline(n+3)(3n+2)(n + 3)(3n + 2)