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Factor.\newline3f2+11f+63f^2 + 11f + 6

Full solution

Q. Factor.\newline3f2+11f+63f^2 + 11f + 6
  1. Identify aa, bb, cc: Identify aa, bb, and cc in the quadratic expression 3f2+11f+63f^2 + 11f + 6 by comparing it with the standard form ax2+bx+cax^2 + bx + c.
    a=3a = 3
    b=11b = 11
    bb00
  2. Find Multiplying Numbers: Find two numbers that multiply to aca*c (36=183*6=18) and add up to bb (1111).\newlineWe need to find two numbers that satisfy these conditions.\newlineAfter checking possible pairs that multiply to 1818 (such as 11 and 1818, 22 and 99, 33 and 36=183*6=1800), we find that 22 and 99 are the numbers we are looking for because 36=183*6=1833 and 36=183*6=1844.
  3. Rewrite Middle Term: Rewrite the middle term, 11f11f, using the two numbers we found, 22 and 99, to split it into two terms.\newline3f2+11f+63f^2 + 11f + 6 can be rewritten as 3f2+2f+9f+63f^2 + 2f + 9f + 6.
  4. Factor by Grouping: Factor by grouping. Group the first two terms together and the last two terms together.\newline(3f2+2f)+(9f+6)(3f^2 + 2f) + (9f + 6)\newlineNow factor out the common factors from each group.\newlineThe common factor in the first group is ff, and in the second group, it is 33.\newlinef(3f+2)+3(3f+2)f(3f + 2) + 3(3f + 2)
  5. Factor out Common Factor: Notice that 3f+23f + 2 is a common factor in both groups. Factor out 3f+23f + 2. The factored form is f+3f + 3(3f+2)(3f + 2).