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Factor.\newline3d2+10d+73d^2 + 10d + 7

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Q. Factor.\newline3d2+10d+73d^2 + 10d + 7
  1. Identify aa, bb, cc: Identify aa, bb, and cc in the quadratic expression 3d2+10d+73d^2 + 10d + 7 by comparing it with the standard form ax2+bx+cax^2 + bx + c.\newlinea=3a = 3\newlineb=10b = 10\newlinebb00
  2. Find Factors and Sum: Find two numbers that multiply to aca*c (which is 37=213*7=21) and add up to bb (which is 1010).\newlineWe need to find two numbers that satisfy these conditions.\newlineAfter checking possible pairs of factors of 2121, we find that 33 and 77 are the numbers we are looking for because:\newline3×7=213 \times 7 = 21\newline3+7=103 + 7 = 10
  3. Rewrite Middle Term: Rewrite the middle term (10d10d) using the two numbers found in the previous step (33 and 77) to split it into two terms.\newline3d2+10d+73d^2 + 10d + 7 can be rewritten as:\newline3d2+3d+7d+73d^2 + 3d + 7d + 7
  4. Factor by Grouping: Factor by grouping. Group the first two terms together and the last two terms together, then factor out the common factors from each group.\newlineFrom 3d2+3d3d^2 + 3d, we can factor out 3d3d:\newline3d(d+1)3d(d + 1)\newlineFrom 7d+77d + 7, we can factor out 77:\newline7(d+1)7(d + 1)\newlineNow we have:\newline3d(d+1)+7(d+1)3d(d + 1) + 7(d + 1)
  5. Factor out Common Factor: Factor out the common binomial factor (d+1)(d + 1) from both terms.\newlineThe factored form of the expression is:\newline(3d+7)(d+1)(3d + 7)(d + 1)