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Factor.\newline2z2+9z+72z^2 + 9z + 7

Full solution

Q. Factor.\newline2z2+9z+72z^2 + 9z + 7
  1. Identify coefficients: Identify the coefficients aa, bb, and cc in the quadratic expression 2z2+9z+72z^2 + 9z + 7 by comparing it to the standard form ax2+bx+cax^2 + bx + c.a=2a = 2, b=9b = 9, c=7c = 7.
  2. Find suitable numbers: Find two numbers that multiply to aca*c (27=142*7 = 14) and add up to bb (99).\newlineThe numbers that satisfy these conditions are 22 and 77 because 27=142*7 = 14 and 2+7=92+7 = 9.
  3. Rewrite middle term: Rewrite the middle term, 9z9z, using the two numbers found in the previous step: 2z2z and 7z7z. The expression becomes 2z2+2z+7z+72z^2 + 2z + 7z + 7.
  4. Factor by grouping: Factor by grouping. Group the first two terms and the last two terms. 2z2+2z2z^2 + 2z + 7z+77z + 7.
  5. Factor out common factor: Factor out the greatest common factor from each group. 2z(z+1)+7(z+1)2z(z + 1) + 7(z + 1).
  6. Final factored form: Since both groups contain the common factor (z+1)(z + 1), factor it out.\newlineThe factored form is (2z+7)(z+1)(2z + 7)(z + 1).