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Factor.\newline2y2+9y+102y^2 + 9y + 10

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Q. Factor.\newline2y2+9y+102y^2 + 9y + 10
  1. Identify aa, bb, cc: Identify aa, bb, and cc in the quadratic expression 2y2+9y+102y^2 + 9y + 10. Compare 2y2+9y+102y^2 + 9y + 10 with ax2+bx+cax^2 + bx + c. a=2a = 2 bb00 bb11
  2. Find two numbers: Find two numbers that multiply to aca*c (which is 210=202*10 = 20) and add up to bb (which is 99).\newlineThe two numbers that satisfy these conditions are 55 and 44, since 54=205*4 = 20 and 5+4=95+4 = 9.
  3. Rewrite middle term: Rewrite the middle term of the quadratic expression using the two numbers found in Step 22.\newline2y2+9y+102y^2 + 9y + 10 can be rewritten as 2y2+5y+4y+102y^2 + 5y + 4y + 10.
  4. Factor by grouping: Factor by grouping.\newlineGroup the terms: 2y2+5y2y^2 + 5y + 4y+104y + 10.\newlineFactor out the common factor from each group.\newlineFrom the first group, factor out yy: y(2y+5)y(2y + 5).\newlineFrom the second group, factor out 44: 4(2y+5)4(2y + 5).
  5. Write factored form: Write the factored form of the expression.\newlineSince both groups contain the common factor (2y+5)(2y + 5), factor this out.\newlineThe factored form is (y+4)(2y+5)(y + 4)(2y + 5).