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Factor.\newline2w2+13w+112w^2 + 13w + 11

Full solution

Q. Factor.\newline2w2+13w+112w^2 + 13w + 11
  1. Identify coefficients: Identify the coefficients aa, bb, and cc in the quadratic expression 2w2+13w+112w^2 + 13w + 11 by comparing it to the standard form ax2+bx+cax^2 + bx + c.a=2a = 2, b=13b = 13, c=11c = 11.
  2. Find suitable numbers: Find two numbers that multiply to aca*c (which is 211=222*11 = 22) and add up to bb (which is 1313).\newlineThe numbers that satisfy these conditions are 22 and 1111 because 211=222*11 = 22 and 2+11=132+11 = 13.
  3. Rewrite middle term: Rewrite the middle term 13w13w using the two numbers found in the previous step.\newlineThe expression becomes 2w2+2w+11w+112w^2 + 2w + 11w + 11.
  4. Factor by grouping: Factor by grouping. Group the first two terms together and the last two terms together.\newlineThis gives us (2w2+2w)+(11w+11)(2w^2 + 2w) + (11w + 11).
  5. Factor out common factors: Factor out the greatest common factor from each group.\newlineFrom the first group, factor out 2w2w, which gives us 2w(w+1)2w(w + 1).\newlineFrom the second group, factor out 1111, which gives us 11(w+1)11(w + 1).
  6. Final factored form: Notice that both groups now have a common factor of w+1w + 1. Factor out the common factor to get the final factored form. The expression becomes 2w+11)(w+12w + 11)(w + 1.