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Factor.\newline2w2+11w+92w^2 + 11w + 9

Full solution

Q. Factor.\newline2w2+11w+92w^2 + 11w + 9
  1. Identify coefficients: Identify the coefficients aa, bb, and cc in the quadratic expression 2w2+11w+92w^2 + 11w + 9 by comparing it to the standard form ax2+bx+cax^2 + bx + c.
    a=2a = 2, b=11b = 11, c=9c = 9
  2. Find suitable numbers: Find two numbers that multiply to aca*c (29=182*9 = 18) and add up to bb (1111).\newlineThe numbers 22 and 99 satisfy these conditions because 29=182*9 = 18 and 2+9=112+9 = 11.
  3. Rewrite middle term: Rewrite the middle term 11w11w using the two numbers found in the previous step.\newline2w2+11w+92w^2 + 11w + 9 can be rewritten as 2w2+2w+9w+92w^2 + 2w + 9w + 9.
  4. Factor by grouping: Factor by grouping. Group the first two terms together and the last two terms together.\newline(2w2+2w)+(9w+9)(2w^2 + 2w) + (9w + 9)
  5. Factor out common factor: Factor out the greatest common factor from each group. 2w(w+1)+9(w+1)2w(w + 1) + 9(w + 1)
  6. Final factorization: Since both groups contain the common factor (w+1)(w + 1), factor this out.(2w+9)(w+1)(2w + 9)(w + 1)