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Factor.\newline2u2+7u+52u^2 + 7u + 5

Full solution

Q. Factor.\newline2u2+7u+52u^2 + 7u + 5
  1. Identify coefficients: Identify the coefficients aa, bb, and cc in the quadratic expression 2u2+7u+52u^2 + 7u + 5 by comparing it to the standard form ax2+bx+cax^2 + bx + c.a=2a = 2, b=7b = 7, c=5c = 5
  2. Find suitable numbers: Find two numbers that multiply to aca*c (25=102*5 = 10) and add up to bb (77).\newlineThe numbers that satisfy these conditions are 22 and 55, since 25=102*5 = 10 and 2+5=72+5 = 7.
  3. Rewrite middle term: Rewrite the middle term, 7u7u, using the two numbers found in the previous step.\newline2u2+7u+52u^2 + 7u + 5 can be rewritten as 2u2+2u+5u+52u^2 + 2u + 5u + 5.
  4. Factor by grouping: Factor by grouping. Group the first two terms together and the last two terms together.\newline(2u2+2u)+(5u+5)(2u^2 + 2u) + (5u + 5)
  5. Factor out common factor: Factor out the greatest common factor from each group. 2u(u+1)+5(u+1)2u(u + 1) + 5(u + 1)
  6. Final factorization: Since both groups contain the common factor (u+1)(u + 1), factor this out.(2u+5)(u+1)(2u + 5)(u + 1)