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Factor.\newline2u2+11u+92u^2 + 11u + 9

Full solution

Q. Factor.\newline2u2+11u+92u^2 + 11u + 9
  1. Identify coefficients: Identify the coefficients aa, bb, and cc in the quadratic expression 2u2+11u+92u^2 + 11u + 9 by comparing it to the standard form ax2+bx+cax^2 + bx + c.
    a=2a = 2, b=11b = 11, c=9c = 9
  2. Find suitable numbers: Find two numbers that multiply to aca*c (29=182*9 = 18) and add up to bb (1111).\newlineThe numbers 22 and 99 satisfy these conditions because 29=182*9 = 18 and 2+9=112+9 = 11.
  3. Rewrite middle term: Rewrite the middle term 11u11u using the two numbers found in the previous step.\newline2u2+11u+92u^2 + 11u + 9 can be rewritten as 2u2+2u+9u+92u^2 + 2u + 9u + 9.
  4. Factor by grouping: Factor by grouping. Group the first two terms together and the last two terms together.\newline(2u2+2u)+(9u+9)(2u^2 + 2u) + (9u + 9)
  5. Factor out common factor: Factor out the greatest common factor from each group. 2u(u+1)+9(u+1)2u(u + 1) + 9(u + 1)
  6. Final factorization: Since both groups contain the common factor (u+1)(u + 1), factor this out.(2u+9)(u+1)(2u + 9)(u + 1)