Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Factor.\newline2t2+9t+102t^2 + 9t + 10

Full solution

Q. Factor.\newline2t2+9t+102t^2 + 9t + 10
  1. Identify aa, bb, cc: Identify aa, bb, and cc in the quadratic expression 2t2+9t+102t^2 + 9t + 10. Compare 2t2+9t+102t^2 + 9t + 10 with ax2+bx+cax^2 + bx + c. a=2a = 2 bb00 bb11
  2. Find two numbers: Find two numbers that multiply to aca*c (which is 210=202*10 = 20) and add up to bb (which is 99).\newlineThe two numbers that satisfy these conditions are 55 and 44, since 54=205*4 = 20 and 5+4=95+4 = 9.
  3. Rewrite middle term: Rewrite the middle term, 9t9t, using the two numbers found in Step 22.\newline2t2+9t+102t^2 + 9t + 10 can be expressed as 2t2+5t+4t+102t^2 + 5t + 4t + 10.
  4. Factor by grouping: Factor by grouping.\newlineGroup the first two terms and the last two terms:\newline(2t2+5t)+(4t+10)(2t^2 + 5t) + (4t + 10)\newlineFactor out the greatest common factor from each group:\newlinet(2t+5)+2(2t+5)t(2t + 5) + 2(2t + 5)
  5. Factor out common binomial: Factor out the common binomial factor.\newlineSince both groups contain the common factor (2t+5)(2t + 5), factor it out:\newline(t+2)(2t+5)(t + 2)(2t + 5)