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Factor.\newline2q29q+72q^2 - 9q + 7

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Q. Factor.\newline2q29q+72q^2 - 9q + 7
  1. Identify aa, bb, cc: Identify aa, bb, and cc in the quadratic expression 2q29q+72q^2 - 9q + 7. Compare 2q29q+72q^2 - 9q + 7 with ax2+bx+cax^2 + bx + c. a=2a = 2 bb00 bb11
  2. Find product and sum: Find two numbers whose product is aca*c (27=142*7 = 14) and whose sum is bb (9-9).\newlineWe need to find two numbers that multiply to 1414 and add up to 9-9.\newlineAfter checking possible pairs of factors of 1414 (11 and 1414, 22 and 27=142*7 = 1400), we find that none of these pairs add up to 9-9.\newlineThis means we cannot factor the quadratic expression using simple factorization methods.
  3. Use quadratic formula: Since the quadratic expression cannot be factored easily, we will use the quadratic formula to find the roots of the equation 2q29q+7=02q^2 - 9q + 7 = 0.\newlineThe quadratic formula is q=b±b24ac2aq = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}.\newlineLet's calculate the discriminant b24acb^2 - 4ac first.\newlineDiscriminant = (9)24(2)(7)(-9)^2 - 4(2)(7) = 8156=2581 - 56 = 25.\newlineSince the discriminant is a perfect square, we can find exact roots.
  4. Calculate discriminant: Calculate the roots using the quadratic formula.\newlineq=(9)±2522q = \frac{-(-9) \pm \sqrt{25}}{2 \cdot 2}\newlineq=9±54q = \frac{9 \pm 5}{4}\newlineWe have two possible values for qq:\newlineq1=(9+5)4=144=3.5q_1 = \frac{(9 + 5)}{4} = \frac{14}{4} = 3.5\newlineq2=(95)4=44=1q_2 = \frac{(9 - 5)}{4} = \frac{4}{4} = 1
  5. Calculate roots: Write the factored form using the roots found.\newlineThe factored form of the quadratic expression is (qq1)(qq2)(q - q_1)(q - q_2).\newlineSubstitute q1q_1 and q2q_2 into the factored form.\newlineFactored form: (q3.5)(q1)(q - 3.5)(q - 1)\newlineHowever, we started with integer coefficients, so we should express the roots as fractions to maintain the form.\newlineq1=72q_1 = \frac{7}{2} (since 3.53.5 is 72\frac{7}{2})\newlineFactored form: (q72)(q1)(q - \frac{7}{2})(q - 1)\newlineTo clear the fraction, multiply each term by 22.\newlineFactored form: (2q7)(q1)(2q - 7)(q - 1)