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Factor.\newline2p2+9p+92p^2 + 9p + 9

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Q. Factor.\newline2p2+9p+92p^2 + 9p + 9
  1. Identify aa, bb, cc: Identify aa, bb, and cc in the quadratic expression 2p2+9p+92p^2 + 9p + 9. Compare 2p2+9p+92p^2 + 9p + 9 with ax2+bx+cax^2 + bx + c. a=2a = 2 bb00 bb11
  2. Find numbers multiply add: Find two numbers that multiply to aca*c (29=182*9 = 18) and add up to bb (99).\newlineWe need to find two numbers that multiply to 1818 and add up to 99.\newlineAfter checking possible pairs that multiply to 1818 (11 and 1818, 22 and 99, 29=182*9 = 1811 and 29=182*9 = 1822), we see that 29=182*9 = 1811 and 29=182*9 = 1822 add up to 99.\newlineTwo numbers: 29=182*9 = 1811, 29=182*9 = 1822
  3. Rewrite middle term: Rewrite the middle term of the quadratic expression using the two numbers found in Step 22.\newline2p2+9p+92p^2 + 9p + 9 can be expressed as 2p2+3p+6p+92p^2 + 3p + 6p + 9.
  4. Factor by grouping: Factor by grouping.\newlineGroup the terms: 2p2+3p2p^2 + 3p + 6p+96p + 9.\newlineFactor out a common factor from each group.\newlineFrom the first group, we can factor out pp: p(2p+3)p(2p + 3).\newlineFrom the second group, we can factor out 33: 3(2p+3)3(2p + 3).
  5. Write factored form: Write the factored form of the expression.\newlineSince both groups contain the common factor (2p+3)(2p + 3), we can factor this out:\newlinep(2p+3)+3(2p+3)=(p+3)(2p+3)p(2p + 3) + 3(2p + 3) = (p + 3)(2p + 3).
  6. Verify factored form: Verify the factored form by expanding it to ensure it matches the original expression. \newline(p+3)(2p+3)=2p2+3p+6p+9=2p2+9p+9(p + 3)(2p + 3) = 2p^2 + 3p + 6p + 9 = 2p^2 + 9p + 9.\newlineThe expanded form matches the original expression, so the factoring is correct.