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Factor.\newline2p2+9p+72p^2 + 9p + 7

Full solution

Q. Factor.\newline2p2+9p+72p^2 + 9p + 7
  1. Identify coefficients: Identify the coefficients aa, bb, and cc in the quadratic expression 2p2+9p+72p^2 + 9p + 7 by comparing it to the standard form ax2+bx+cax^2 + bx + c.a=2a = 2, b=9b = 9, c=7c = 7
  2. Find two numbers: Find two numbers that multiply to aca*c (27=142*7 = 14) and add up to bb (99).\newlineThe numbers that satisfy these conditions are 22 and 77 because 27=142*7 = 14 and 2+7=92+7 = 9.
  3. Rewrite middle term: Rewrite the middle term 9p9p using the two numbers found in the previous step.\newline2p2+9p+72p^2 + 9p + 7 can be rewritten as 2p2+2p+7p+72p^2 + 2p + 7p + 7.
  4. Factor by grouping: Factor by grouping. Group the terms into two pairs and factor out the common factor from each pair.\newlineFrom the first pair 2p2+2p2p^2 + 2p, factor out 2p2p to get 2p(p+1)2p(p + 1).\newlineFrom the second pair 7p+77p + 7, factor out 77 to get 7(p+1)7(p + 1).
  5. Factor out common binomial: Now that we have 2p(p+1)+7(p+1)2p(p + 1) + 7(p + 1), we can factor out the common binomial factor (p+1)(p + 1). The factored form is (2p+7)(p+1)(2p + 7)(p + 1).