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Factor.\newline2n2+9n+102n^2 + 9n + 10

Full solution

Q. Factor.\newline2n2+9n+102n^2 + 9n + 10
  1. Identify coefficients: Identify the coefficients aa, bb, and cc in the quadratic expression 2n2+9n+102n^2 + 9n + 10 by comparing it to the standard form ax2+bx+cax^2 + bx + c.a=2a = 2, b=9b = 9, c=10c = 10
  2. Find two numbers: Find two numbers that multiply to aca*c (210=202*10 = 20) and add up to bb (99).\newlineThe numbers that satisfy these conditions are 44 and 55 because 45=204*5 = 20 and 4+5=94+5 = 9.
  3. Rewrite middle term: Rewrite the middle term, 9n9n, using the two numbers found in the previous step: 4n4n and 5n5n. The expression becomes 2n2+4n+5n+102n^2 + 4n + 5n + 10.
  4. Factor by grouping: Factor by grouping. Group the first two terms and the last two terms separately. 2n2+4n2n^2 + 4n + 5n+105n + 10
  5. Factor out common factor: Factor out the greatest common factor from each group. 2n(n+2)+5(n+2)2n(n + 2) + 5(n + 2)
  6. Final factored form: Since both groups contain the common factor (n+2)(n + 2), factor it out.\newlineThe factored form of the expression is (2n+5)(n+2)(2n + 5)(n + 2).