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Factor.\newline2f2+7f+52f^2 + 7f + 5

Full solution

Q. Factor.\newline2f2+7f+52f^2 + 7f + 5
  1. Identify coefficients: Identify the coefficients aa, bb, and cc in the quadratic expression 2f2+7f+52f^2 + 7f + 5 by comparing it to the standard form ax2+bx+cax^2 + bx + c.a=2a = 2, b=7b = 7, c=5c = 5
  2. Find two numbers: Find two numbers that multiply to aca*c (25=102*5 = 10) and add up to bb (77).\newlineThe numbers that satisfy these conditions are 22 and 55 because 25=102*5 = 10 and 2+5=72+5 = 7.
  3. Rewrite middle term: Rewrite the middle term, 7f7f, using the two numbers found in the previous step: 2f2f and 5f5f. The expression becomes 2f2+2f+5f+52f^2 + 2f + 5f + 5.
  4. Factor by grouping: Factor by grouping. Group the first two terms and the last two terms separately.\newline(2f2+2f)+(5f+5)(2f^2 + 2f) + (5f + 5)
  5. Factor out common factor: Factor out the greatest common factor from each group.\newline2f(f+1)+5(f+1)2f(f + 1) + 5(f + 1)
  6. Final factored form: Since both groups contain the common factor (f+1)(f + 1), factor it out.\newlineThe factored form of the expression is (2f+5)(f+1)(2f + 5)(f + 1).