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Factor.\newline2f2+11f+92f^2 + 11f + 9

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Q. Factor.\newline2f2+11f+92f^2 + 11f + 9
  1. Identify aa, bb, cc: Identify aa, bb, and cc in the quadratic expression 2f2+11f+92f^2 + 11f + 9. Compare 2f2+11f+92f^2 + 11f + 9 with ax2+bx+cax^2 + bx + c. a=2a = 2 bb00 bb11
  2. Find numbers multiply add: Find two numbers that multiply to aca*c (29=182*9 = 18) and add up to bb (1111).\newlineWe need to find two numbers that multiply to 1818 and add up to 1111.\newlineAfter checking possible pairs of factors of 1818 (11 and 1818, 22 and 29=182*9 = 1800, 29=182*9 = 1811 and 29=182*9 = 1822), we find that 22 and 29=182*9 = 1800 are the correct pair because 29=182*9 = 1855.
  3. Rewrite middle term: Rewrite the middle term 11f11f using the two numbers found in Step 22.\newlineThe expression 2f2+11f+92f^2 + 11f + 9 can be rewritten by splitting the middle term into 2f2f and 9f9f.\newline2f2+11f+9=2f2+2f+9f+92f^2 + 11f + 9 = 2f^2 + 2f + 9f + 9
  4. Factor by grouping: Factor by grouping.\newlineFirst, group the terms: 2f2+2f2f^2 + 2f + 9f+99f + 9.\newlineNow, factor out the common factors from each group.\newlineFrom the first group, factor out 2f2f: 2f(f+1)2f(f + 1).\newlineFrom the second group, factor out 99: 9(f+1)9(f + 1).
  5. Factor out common binomial: Factor out the common binomial (f+1)(f + 1). We have 2f(f+1)+9(f+1)2f(f + 1) + 9(f + 1). Factor out the common binomial (f+1)(f + 1) to get (f+1)(2f+9)(f + 1)(2f + 9).