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Factor 
27v^(3)+1 completely.
Answer:

Factor 27v3+1 27 v^{3}+1 completely.\newlineAnswer:

Full solution

Q. Factor 27v3+1 27 v^{3}+1 completely.\newlineAnswer:
  1. Identify Type and Approach: Identify the type of expression and the approach to factor it.\newlineThe expression 27v3+127v^3 + 1 is a sum of cubes, which can be factored using the sum of cubes formula: a3+b3=(a+b)(a2ab+b2)a^3 + b^3 = (a + b)(a^2 - ab + b^2).
  2. Identify 'a' and 'b': Identify 'a' and 'b' in the sum of cubes formula.\newlineIn the expression 27v3+127v^3 + 1, we can see that 27v327v^3 is the cube of 3v3v (since (3v)3=27v3(3v)^3 = 27v^3) and 11 is the cube of 11 (since 13=11^3 = 1). So, a=3va = 3v and b=1b = 1.
  3. Apply Sum of Cubes Formula: Apply the sum of cubes formula.\newlineUsing the values of 'a' and 'b' from Step 22, we apply the sum of cubes formula:\newline27v3+1=(3v)3+13=(3v+1)((3v)2(3v)(1)+12)27v^3 + 1 = (3v)^3 + 1^3 = (3v + 1)((3v)^2 - (3v)(1) + 1^2).
  4. Simplify Factored Expression: Simplify the factored expression.\newlineNow we simplify the expression inside the parentheses:\newline(3v+1)(9v23v+1)(3v + 1)(9v^2 - 3v + 1).
  5. Check for Further Factoring: Check the factored expression for possible further factoring.\newlineThe quadratic expression 9v23v+19v^2 - 3v + 1 does not factor further over the integers, so the factoring is complete.