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Factor.\newline25x2925x^2 - 9

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Q. Factor.\newline25x2925x^2 - 9
  1. Approach Determination: Determine the approach to factor 25x2925x^2 - 9. We can observe that 25x225x^2 and 99 are both perfect squares, and they are being subtracted from each other. This suggests that we can use the difference of squares formula, which is a2b2=(ab)(a+b)a^2 - b^2 = (a - b)(a + b).
  2. Form Identification: Identify 25x2925x^2 - 9 in the form of a2b2a^2 - b^2.
    25x225x^2 can be written as (5x)2(5x)^2 because 5x×5x=25x25x \times 5x = 25x^2.
    99 can be written as 323^2 because 3×3=93 \times 3 = 9.
    So, 25x2925x^2 - 9 can be rewritten as (5x)232(5x)^2 - 3^2.
  3. Formula Application: Apply the difference of squares formula to factor the expression.\newlineUsing the formula a2b2=(ab)(a+b)a^2 - b^2 = (a - b)(a + b), we substitute aa with 5x5x and bb with 33.\newline(5x)232=(5x3)(5x+3)(5x)^2 - 3^2 = (5x - 3)(5x + 3).
  4. Final Factored Form: Write the final factored form.\newlineThe factored form of 25x2925x^2 - 9 is (5x3)(5x+3)(5x - 3)(5x + 3).