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Factor.\newline25t2925t^2 - 9

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Q. Factor.\newline25t2925t^2 - 9
  1. Approach Determination: Determine the approach to factor 25t2925t^2 - 9. We can observe that 25t225t^2 and 99 are both perfect squares, and they are being subtracted from each other. This suggests that we can use the difference of squares formula, which is a2b2=(ab)(a+b)a^2 - b^2 = (a - b)(a + b).
  2. Identify Form: Identify 25t2925t^2 - 9 in the form of a2b2a^2 - b^2.\newline25t225t^2 can be written as (5t)2(5t)^2 because 5t×5t=25t25t \times 5t = 25t^2.\newline99 can be written as 323^2 because 3×3=93 \times 3 = 9.\newlineSo, 25t2925t^2 - 9 can be rewritten as (5t)232(5t)^2 - 3^2.
  3. Apply Formula: Apply the difference of squares formula to factor the expression.\newlineUsing the formula a2b2=(ab)(a+b)a^2 - b^2 = (a - b)(a + b), we substitute aa with 5t5t and bb with 33.\newline(5t)232=(5t3)(5t+3)(5t)^2 - 3^2 = (5t - 3)(5t + 3).
  4. Write Factored Form: Write down the factored form of the expression.\newlineThe factored form of 25t2925t^2 - 9 is (5t3)(5t+3)(5t - 3)(5t + 3).