Factor. 25c^2 - 16 ______

Determine factoring technique: Determine the appropriate factoring technique for 25c^2 - 16. Since we have a difference of squares, we can use the formula a^2 - b^2 = (a - b)(a + b).Identify perfect squares: Identify the terms in the expression 25c^2 - 16 as perfect squares. 25c^2 can be written as (5c)^2 because 5c * 5c = 25c^2. 16 can be written as 4^2 because 4 * 4 = 16. So, 25c^2 - 16 is in the form of a^2 - b^2 where a = 5c and b = 4.Apply difference of squares formula: Apply the difference of squares formula to factor the expression. Using a = 5c and b = 4, we get: 25c^2 - 16 = (5c)^2 - 4^2 = (5c - 4)(5c + 4).

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Math Problems

Algebra 1

Factor quadratics: special cases

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Q. Factor.

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25c^2 - 16

Determine factoring technique: Determine the appropriate factoring technique for $25c^2 - 16$ . Since we have a difference of squares, we can use the formula $a^2 - b^2 = (a - b)(a + b)$ .
Identify perfect squares: Identify the terms in the expression $25c^2 - 16$ as perfect squares. $\newline$ $25c^2$ can be written as $(5c)^2$ because $5c \times 5c = 25c^2$ . $\newline$ $16$ can be written as $4^2$ because $4 \times 4 = 16$ . $\newline$ So, $25c^2 - 16$ is in the form of $a^2 - b^2$ where $a = 5c$ and $25c^2$ $0$ .
Apply difference of squares formula: Apply the difference of squares formula to factor the expression. $\newline$ Using $a = 5c$ and $b = 4$ , we get: $\newline$ $25c^2 - 16 = (5c)^2 - 4^2 = (5c - 4)(5c + 4)$ .