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Factor.\newline20x3+10x2+2x+120x^3 + 10x^2 + 2x + 1

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Q. Factor.\newline20x3+10x2+2x+120x^3 + 10x^2 + 2x + 1
  1. Identify Factors: Identify common factors in all terms.\newlineWe look for the greatest common factor (GCF) that can be factored out from all terms of the polynomial 20x3+10x2+2x+120x^3 + 10x^2 + 2x + 1.\newlineThe GCF of 20x320x^3, 10x210x^2, 2x2x, and 11 is 11, which means we cannot factor out a common numerical factor. However, there is no common variable factor either, as the constant term 11 does not contain any variable.
  2. Group for Factoring: Group terms to factor by grouping.\newlineSince there is no common factor, we attempt to factor by grouping. We can group the terms as follows: 20x3+10x220x^3 + 10x^2 + 2x+12x + 1.\newlineNow we look for common factors within each group.
  3. Factor Grouped Terms: Factor out the common factors from each group.\newlineFrom the first group 20x3+10x220x^3 + 10x^2, we can factor out 10x210x^2, which gives us 10x2(2x+1)10x^2(2x + 1).\newlineFrom the second group 2x+12x + 1, we notice that there is no common factor other than 11, and the group itself is a binomial that matches the binomial in the first group.\newlineSo we have 10x2(2x+1)+1(2x+1)10x^2(2x + 1) + 1(2x + 1).
  4. Factor Common Binomial: Factor out the common binomial factor.\newlineWe now have a common binomial factor of (2x+1)(2x + 1) in both terms. We can factor this out to get:\newline(2x+1)(10x2+1)(2x + 1)(10x^2 + 1).
  5. Check Further Factoring: Check for further factoring possibilities.\newlineWe need to check if the remaining quadratic 10x2+110x^2 + 1 can be factored further. This is a sum of squares, which cannot be factored over the real numbers. Therefore, our factoring process is complete.