Factor. 18y^3 + 9y^2 + 14y + 7 ______

Identify Common Factors: Look for common factors in the first two terms and the last two terms separately. For the first two terms, 18y^3 and 9y^2, the common factor is 9y^2. For the last two terms, 14y and 7, the common factor is 7.Factor Out Common Factors: Factor out the common factors from the terms identified in Step 1. Factor out 9y^2 from 18y^3 and 9y^2. 18y^3 + 9y^2 = 9y^2(2y + 1) Factor out 7 from 14y and 7. 14y + 7 = 7(2y + 1)Use Common Binomial Factor: Observe that both groups now have a common binomial factor of (2y + 1). Write the expression as a product of the common binomial factor and the remaining factors. 9y^2(2y + 1) + 7(2y + 1) = (9y^2 + 7)(2y + 1)

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Q. Factor.

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18y^3 + 9y^2 + 14y + 7

Identify Common Factors: Look for common factors in the first two terms and the last two terms separately. $\newline$ For the first two terms, $18y^3$ and $9y^2$ , the common factor is $9y^2$ . $\newline$ For the last two terms, $14y$ and $7$ , the common factor is $7$ .
Factor Out Common Factors: Factor out the common factors from the terms identified in Step $1$ . $\newline$ Factor out $9y^2$ from $18y^3$ and $9y^2$ . $\newline$ $18y^3 + 9y^2 = 9y^2(2y + 1)$ $\newline$ Factor out $7$ from $14y$ and $7$ . $\newline$ $14y + 7 = 7(2y + 1)$
Use Common Binomial Factor: Observe that both groups now have a common binomial factor of $(2y + 1)$ . Write the expression as a product of the common binomial factor and the remaining factors. $9y^2(2y + 1) + 7(2y + 1) = (9y^2 + 7)(2y + 1)$