Factor. 18h^3 + 9h^2 + 16h + 8 ______

Factor Common Terms: Look for common factors in the first two terms and the last two terms separately. First two terms: 18h^3 + 9h^2 can be factored by taking out 9h^2 as a common factor. 9h^2(2h + 1) Last two terms: 16h + 8 can be factored by taking out 8 as a common factor. 8(2h + 1)Combine Terms: Now we have: 9h^2(2h + 1) + 8(2h + 1) Notice that (2h + 1) is a common factor in both terms. We can factor (2h + 1) out of the expression. (2h + 1)(9h^2 + 8)Final Factored Form: Check for any further factoring possibilities. The terms inside the second set of parentheses, 9h^2 + 8, do not have any common factors and cannot be factored further. So, the factored form of the polynomial is: (2h + 1)(9h^2 + 8)

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18h^3 + 9h^2 + 16h + 8

Factor Common Terms: Look for common factors in the first two terms and the last two terms separately. $\newline$ First two terms: $18h^3 + 9h^2$ can be factored by taking out $9h^2$ as a common factor. $\newline$ $9h^2(2h + 1)$ $\newline$ Last two terms: $16h + 8$ can be factored by taking out $8$ as a common factor. $\newline$ $8(2h + 1)$
Combine Terms: Now we have: $\newline$ $9h^2(2h + 1) + 8(2h + 1)$ $\newline$ Notice that $(2h + 1)$ is a common factor in both terms. $\newline$ We can factor $(2h + 1)$ out of the expression. $\newline$ $(2h + 1)(9h^2 + 8)$
Final Factored Form: Check for any further factoring possibilities. $\newline$ The terms inside the second set of parentheses, $9h^2 + 8$ , do not have any common factors and cannot be factored further. $\newline$ So, the factored form of the polynomial is: $\newline$ $(2h + 1)(9h^2 + 8)$