Factor. 16st + 8s + 18t + 9 ______

Identify Common Factors: Look for common factors in each pair of terms. We can group the terms as (16st + 8s) and (18t + 9) to look for common factors.Factor Out First Group: Factor out the common factor from the first group. In the first group (16st + 8s), the common factor is 8s. So, 16st + 8s = 8s(2t + 1).Factor Out Second Group: Factor out the common factor from the second group. In the second group (18t + 9), the common factor is 9. So, 18t + 9 = 9(2t + 1).Check for Common Binomial Factor: Check if both groups have a common binomial factor. Both groups have the common binomial factor (2t + 1).Factor Out Common Binomial Factor: Factor out the common binomial factor. Since both groups have the common binomial factor (2t + 1), we can factor it out. The expression becomes (8s + 9)(2t + 1).

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Algebra 1

Factor quadratics: special cases

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Q. Factor.

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16st + 8s + 18t + 9

Identify Common Factors: Look for common factors in each pair of terms. $\newline$ We can group the terms as $16st + 8s$ and $18t + 9$ to look for common factors.
Factor Out First Group: Factor out the common factor from the first group. $\newline$ In the first group $16st + 8s$ , the common factor is $8s$ . $\newline$ So, $16st + 8s = 8s(2t + 1)$ .
Factor Out Second Group: Factor out the common factor from the second group. $\newline$ In the second group $(18t + 9)$ , the common factor is $9$ . $\newline$ So, $18t + 9 = 9(2t + 1)$ .
Check for Common Binomial Factor: Check if both groups have a common binomial factor. $\newline$ Both groups have the common binomial factor $2t + 1$ .
Factor Out Common Binomial Factor: Factor out the common binomial factor. $\newline$ Since both groups have the common binomial factor $(2t + 1)$ , we can factor it out. $\newline$ The expression becomes $(8s + 9)(2t + 1)$ .