Factor. 16s^2 - 25 ______

Determine Factoring Technique: Determine the appropriate factoring technique for 16s^2 - 25. Since we have a difference of squares, we can use the formula a^2 - b^2 = (a - b)(a + b).Identify Perfect Squares: Identify the terms in the expression 16s^2 - 25 as perfect squares. 16s^2 can be written as (4s)^2 because 4s * 4s = 16s^2. 25 can be written as 5^2 because 5 * 5 = 25. So, 16s^2 - 25 is in the form of a^2 - b^2 where a = 4s and b = 5.Apply Difference of Squares Formula: Apply the difference of squares formula to factor the expression. Using a = 4s and b = 5, we get: 16s^2 - 25 = (4s)^2 - 5^2 = (4s - 5)(4s + 5).

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Math Problems

Algebra 1

Factor quadratics: special cases

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Q. Factor.

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16s^2 - 25

Determine Factoring Technique: Determine the appropriate factoring technique for $16s^2 - 25$ . Since we have a difference of squares, we can use the formula $a^2 - b^2 = (a - b)(a + b)$ .
Identify Perfect Squares: Identify the terms in the expression $16s^2 - 25$ as perfect squares. $\newline$ $16s^2$ can be written as $(4s)^2$ because $4s \times 4s = 16s^2$ . $\newline$ $25$ can be written as $5^2$ because $5 \times 5 = 25$ . $\newline$ So, $16s^2 - 25$ is in the form of $a^2 - b^2$ where $a = 4s$ and $16s^2$ $0$ .
Apply Difference of Squares Formula: Apply the difference of squares formula to factor the expression. $\newline$ Using $a = 4s$ and $b = 5$ , we get: $\newline$ $16s^2 - 25 = (4s)^2 - 5^2 = (4s - 5)(4s + 5)$ .