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Factor.\newline15u3+20u23u415u^3 + 20u^2 - 3u - 4

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Q. Factor.\newline15u3+20u23u415u^3 + 20u^2 - 3u - 4
  1. Group terms: Group terms to find common factors.\newlineGroup the first two terms and the last two terms separately.\newline15u3+20u23u415u^3 + 20u^2 - 3u - 4 can be written as (15u3+20u2)+(3u4)(15u^3 + 20u^2) + (-3u - 4).
  2. Factor common terms: Factor out the greatest common factor from each group.\newlineFrom the first group 15u3+20u215u^3 + 20u^2, we can factor out 5u25u^2, giving us 5u2(3u+4)5u^2(3u + 4).\newlineFrom the second group 3u4-3u - 4, we can factor out 1-1, giving us 1(3u+4)-1(3u + 4).\newlineNow we have 5u2(3u+4)1(3u+4)5u^2(3u + 4) - 1(3u + 4).
  3. Factor binomial: Factor out the common binomial factor.\newlineBoth groups contain the common factor (3u+4)(3u + 4).\newlineFactor out (3u+4)(3u + 4) from both groups.\newlineThis gives us (3u+4)(5u21)(3u + 4)(5u^2 - 1).
  4. Factor difference of squares: Factor the difference of squares if possible.\newlineThe second term 5u215u^2 - 1 is a difference of squares and can be factored further.\newline5u215u^2 - 1 can be written as (5u)2(1)2(\sqrt{5}u)^2 - (1)^2, which is a difference of squares.\newlineFactoring this gives us (5u1)(5u+1)(\sqrt{5}u - 1)(\sqrt{5}u + 1).
  5. Write final form: Write the final factored form. Combine the factored terms to get the final factored form of the original polynomial. The final factored form is (3u+4)(5u1)(5u+1)(3u + 4)(\sqrt{5}u - 1)(\sqrt{5}u + 1).