Factor. 14u^3 + 7u^2 + 16u + 8 ______

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Identify Factors: Identify common factors in each pair of terms. We can group the terms as (14u^3 + 7u^2) and (16u + 8). Now, we look for common factors in each group. For the first group (14u^3 + 7u^2), the common factor is 7u^2. For the second group (16u + 8), the common factor is 8.Factor Out Common Factors: Factor out the common factors from each group. From the first group, we factor out 7u^2, which gives us 7u^2(2u + 1). From the second group, we factor out 8, which gives us 8(2u + 1). Now we have 7u^2(2u + 1) + 8(2u + 1).Factor Out Binomial Factor: Factor out the common binomial factor. We notice that (2u + 1) is a common factor in both terms. We can factor (2u + 1) out, which gives us (2u + 1)(7u^2 + 8).Check for Further Factoring: Check the factored form for any possible further factoring. The first factor (2u + 1) is a binomial that cannot be factored further. The second factor (7u^2 + 8) is a binomial with no common factors and does not represent a difference of squares or any other factorable form. Therefore, the factored form is fully simplified.

Factor. $\newline$ $14u^3 + 7u^2 + 16u + 8$

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Factor.\newline14u3+7u2+16u+814u^3 + 7u^2 + 16u + 814u3+7u2+16u+8

Factor. $\newline$ $14u^3 + 7u^2 + 16u + 8$