Factor. 14rs - 7r + 6s - 3 ______

Identify Factors: Identify common factors in pairs of terms. We can group the terms as follows: (14rs - 7r) + (6s - 3). Now, we look for common factors in each group. In the first group (14rs - 7r), the common factor is 7r. In the second group (6s - 3), the common factor is 3.Factor Out Common Factors: Factor out the common factors from each group. From the first group, we factor out 7r, getting 7r(2s - 1). From the second group, we factor out 3, getting 3(2s - 1). Now we have: 7r(2s - 1) + 3(2s - 1).Factor Out Binomial Factor: Factor out the common binomial factor. We notice that (2s - 1) is a common factor in both terms. We factor (2s - 1) out of the expression, getting (2s - 1)(7r + 3).

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Q. Factor.

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14rs - 7r + 6s - 3

Identify Factors: Identify common factors in pairs of terms. $\newline$ We can group the terms as follows: $14rs - 7r$ + $6s - 3$ . $\newline$ Now, we look for common factors in each group. $\newline$ In the first group $14rs - 7r$ , the common factor is $7r$ . $\newline$ In the second group $6s - 3$ , the common factor is $3$ .
Factor Out Common Factors: Factor out the common factors from each group. $\newline$ From the first group, we factor out $7r$ , getting $7r(2s - 1)$ . $\newline$ From the second group, we factor out $3$ , getting $3(2s - 1)$ . $\newline$ Now we have: $7r(2s - 1) + 3(2s - 1)$ .
Factor Out Binomial Factor: Factor out the common binomial factor. $\newline$ We notice that $(2s - 1)$ is a common factor in both terms. $\newline$ We factor $(2s - 1)$ out of the expression, getting $(2s - 1)(7r + 3)$ .