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Factor.\newline10u320u2+3u610u^3 - 20u^2 + 3u - 6

Full solution

Q. Factor.\newline10u320u2+3u610u^3 - 20u^2 + 3u - 6
  1. Identify Common Factors: Look for common factors in the first two terms and the last two terms separately.\newlineFor the first two terms, 10u310u^3 and 20u2-20u^2, the common factor is 10u210u^2.\newlineFor the last two terms, 3u3u and 6-6, the common factor is 33.
  2. Factor Out Common Factors: Factor out the common factors from the first two terms and the last two terms.\newline10u320u210u^3 - 20u^2 can be factored as 10u2(u2)10u^2(u - 2).\newline3u63u - 6 can be factored as 3(u2)3(u - 2).
  3. Rewrite Polynomial: Rewrite the polynomial with the factored terms.\newlineThe polynomial now looks like this: 10u2(u2)+3(u2)10u^2(u - 2) + 3(u - 2).
  4. Factor Out Binomial Factor: Factor out the common binomial factor (u2)(u - 2) from both terms.\newlineThe polynomial can now be written as (u2)(10u2+3)(u - 2)(10u^2 + 3).
  5. Check for Further Factoring: Check if the second term 10u2+310u^2 + 3 can be factored further.\newlineSince 10u2+310u^2 + 3 has no common factors and is not a difference of squares or a perfect square trinomial, it cannot be factored further.