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Factor 
1-p^(3) completely.
Answer:

Factor 1p3 1-p^{3} completely.\newlineAnswer:

Full solution

Q. Factor 1p3 1-p^{3} completely.\newlineAnswer:
  1. Identify expression: Identify the expression to be factored. 1p31 - p^3 is a difference of cubes since it can be written as a3b3a^3 - b^3 where a=1a = 1 and b=pb = p.
  2. Recall formula: Recall the formula for factoring a difference of cubes.\newlineThe formula for factoring a3b3a^3 - b^3 is (ab)(a2+ab+b2)(a - b)(a^2 + ab + b^2).
  3. Apply formula: Apply the formula to the given expression.\newlineUsing the formula, we have a=1a = 1 and b=pb = p, so the factorization of 1p31 - p^3 is (1p)(12+1p+p2)(1 - p)(1^2 + 1\cdot p + p^2).
  4. Simplify factors: Simplify the factors.\newline(1p)(1+p+p2)(1 - p)(1 + p + p^2) simplifies to (1p)(1+p+p2)(1 - p)(1 + p + p^2) since 12=11^2 = 1.

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