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f(x)=x(x-3)(x+4)(x+5)
How many distinct zeroes does the function have?

f(x)=x(x3)(x+4)(x+5) f(x)=x(x-3)(x+4)(x+5) \newlineHow many distinct zeroes does the function have?

Full solution

Q. f(x)=x(x3)(x+4)(x+5) f(x)=x(x-3)(x+4)(x+5) \newlineHow many distinct zeroes does the function have?
  1. Identify zeroes of the function: Identify the zeroes of the function by setting each factor equal to zero.\newlinex(x3)(x+4)(x+5)=0x(x-3)(x+4)(x+5) = 0\newlineThe zeroes occur when x=0x = 0, x=3x = 3, x=4x = -4, or x=5x = -5.
  2. Check for repeated zeroes: Check for any repeated zeroes. Each zero corresponds to a different factor in the function, so there are no repeated zeroes.
  3. Count distinct zeroes: Count the number of distinct zeroes.\newlineThere are 44 distinct factors that can be set to zero, so there are 44 distinct zeroes.

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