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f(x)=x^(2)-6x

g(x)=sqrtx
Evaluate.

f(g(25))=

$f(x)=x^{2}-6 x$ $\newline$ $g(x)=\sqrt{x}$ $\newline$ Evaluate. $\newline$ $f(g(25))=$

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Domain and range of square root functions: equations

Full solution

Q.

f(x)=x^{2}-6 x

\newline

g(x)=\sqrt{x}

\newline

Evaluate.

\newline

f(g(25))=

Evaluate $g(25)$ : First, we need to evaluate $g(25)$ which is the square root of $25$ . $\newline$ $g(25) = \sqrt{25}$ $\newline$ $g(25) = 5$
Substitute into $f(x)$ : Now that we have $g(25) = 5$ , we will substitute this value into the function $f(x)$ . $\newline$ $f(g(25)) = f(5)$ $\newline$ $f(5) = 5^2 - 6 \times 5$
Calculate $f(5)$ : Next, we calculate the value of $f(5)$ by performing the operations. $f(5) = 25 - 30$ $f(5) = -5$
Find $f(g(25))$ : We have found the value of $f(g(25))$ , which is $-5$ .

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