f(x)={[-(x-1)^(2)+1," for ",1 4]:} Find f(4) Answer:

Identify Interval for x=4: Identify the correct piece of the piecewise function to use for x = 4. The function f(x) is defined differently for different intervals of x. Since we are looking for f(4), we need to use the definition of f(x) that applies when x = 4.Use Definition for x=4: Use the definition of f(x) for x = 4. According to the given piecewise function, f(x) = -1 when x = 4.Calculate f(4): Calculate the value of f(4). Since f(x) = -1 for x = 4, we have f(4) = -1.

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

$f(x)={[-(x-1)^(2)+1," for ",1 <= x < 4],[-1," for ",x=4],[6x-32," for ",x > 4]:} Find f(4) Answer:$

$f(x)=\left\{\begin{array}{lll} -(x-1)^{2}+1 & \text { for } & 1 \leq x<4 \\ -1 & \text { for } & x=4 \\ 6 x-32 & \text { for } & x>4 \end{array}\right.$ $\newline$ Find $f(4)$ $\newline$ Answer: $\newline$

View step-by-step help

Home

Math Problems

Algebra 2

Transformations of quadratic functions

Full solution

f(x)=\left\{\begin{array}{lll} -(x-1)^{2}+1 & \text { for } & 1 \leq x<4 \\ -1 & \text { for } & x=4 \\ 6 x-32 & \text { for } & x>4 \end{array}\right.

\newline

Find

f(4)

\newline

Answer:

\newline

Identify Interval for $x=4$ : Identify the correct piece of the piecewise function to use for $x = 4$ . $\newline$ The function $f(x)$ is defined differently for different intervals of $x$ . Since we are looking for $f(4)$ , we need to use the definition of $f(x)$ that applies when $x = 4$ .
Use Definition for $x=4$ : Use the definition of $f(x)$ for $x = 4$ . According to the given piecewise function, $f(x) = -1$ when $x = 4$ .
Calculate $f(4)$ : Calculate the value of $f(4)$ . $\newline$ Since $f(x) = -1$ for $x = 4$ , we have $f(4) = -1$ .