Given the quadratic function:(x)=9x^(2)-60 x+80 Find the 𝑥 x-intercepts

Identify coefficients: Identify the coefficients of the quadratic equation f(x) = 9x^2 - 60x + 80. - a = 9, b = -60, c = 80Find vertex x-coordinate: Use the vertex formula x = -b/(2a) to find the x-coordinate of the vertex. - x = -(-60)/(2*9) - x = 60/18 - x = 10/3Find vertex y-coordinate: Substitute x = 10/3 into the function to find the y-coordinate of the vertex. - f(10/3) = 9(10/3)^2 - 60(10/3) + 80 - f(10/3) = 9(100/9) - 200 + 80 - f(10/3) = 100 - 200 + 80 - f(10/3) = -20

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Given the quadratic function:(x)=9x^(2)-60 x+80
Find the
𝑥
x-intercepts

Given the quadratic function: $f(x)=9x^{2}-60x+80$ $\newline$ Find the $𝑥$ -intercepts.

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Algebra 2

Solve complex trigonomentric equations

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Q. Given the quadratic function:

f(x)=9x^{2}-60x+80

\newline

Find the

𝑥

-intercepts.

Identify coefficients: Identify the coefficients of the quadratic equation $f(x) = 9x^2 - 60x + 80$ . $\newline$ - $a = 9$ , $b = -60$ , $c = 80$
Find vertex x-coordinate: Use the vertex formula $x = -\frac{b}{2a}$ to find the x-coordinate of the vertex. $\newline$ - $x = -\frac{-60}{2\cdot 9}$ $\newline$ - $x = \frac{60}{18}$ $\newline$ - $x = \frac{10}{3}$
Find vertex y-coordinate: Substitute $x = \frac{10}{3}$ into the function to find the y-coordinate of the vertex. $\newline$ - $f\left(\frac{10}{3}\right) = 9\left(\frac{10}{3}\right)^2 - 60\left(\frac{10}{3}\right) + 80$ $\newline$ - $f\left(\frac{10}{3}\right) = 9\left(\frac{100}{9}\right) - 200 + 80$ $\newline$ - $f\left(\frac{10}{3}\right) = 100 - 200 + 80$ $\newline$ - $f\left(\frac{10}{3}\right) = -20$