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f(x)=52xx23f(x)=\frac{5}{\sqrt[3]{2x-x^{2}}}

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Q. f(x)=52xx23f(x)=\frac{5}{\sqrt[3]{2x-x^{2}}}
  1. Understand and Identify Cube Root: We are given the function f(x)=52xx23f(x)=\frac{5}{\sqrt[3]{2x-x^{2}}}. The first step is to understand the function and identify the cube root in the denominator.
  2. Rewrite Cube Root as Fractional Exponent: The cube root of a variable expression can be written as a fractional exponent. So, we rewrite the cube root in the denominator as a power of 13\frac{1}{3}.\newlinef(x)=5(2xx2)13f(x) = \frac{5}{(2x - x^2)^{\frac{1}{3}}}
  3. Check and Simplify Quadratic Expression: Now, we need to check if the expression inside the cube root, 2xx22x - x^2, can be simplified further. This is a quadratic expression, and we should look for common factors or if it can be factored.
  4. Factorize Quadratic Expression: The expression 2xx22x - x^2 can be factored by taking xx as a common factor.\newlinex(2x)=2xx2x(2 - x) = 2x - x^2
  5. Substitute Factored Form: Now we substitute the factored form back into the function.\newlinef(x)=5(x(2x))13f(x) = \frac{5}{(x(2 - x))^{\frac{1}{3}}}
  6. Apply Property of Exponents: Since we have factored the expression inside the cube root, we can now apply the property of exponents which states that (ab)13=a13×b13(ab)^{\frac{1}{3}} = a^{\frac{1}{3}} \times b^{\frac{1}{3}}.f(x)=5x13×(2x)13f(x) = \frac{5}{x^{\frac{1}{3}} \times (2 - x)^{\frac{1}{3}}}
  7. Final Simplification: The function is now simplified as much as possible. We cannot simplify it further without knowing the specific value of xx.

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