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f(x)={[-5," for ",x < 3],[2," for ",x=3],[-(x-4)^(2)+5," for ",x > 3]:}
Find 
f(2)
Answer:

f(x)={5amp; for amp;xlt;32amp; for amp;x=3(x4)2+5amp; for amp;xgt;3 f(x)=\left\{\begin{array}{lll} -5 &amp; \text { for } &amp; x&lt;3 \\ 2 &amp; \text { for } &amp; x=3 \\ -(x-4)^{2}+5 &amp; \text { for } &amp; x&gt;3 \end{array}\right. \newlineFind f(2) f(2) \newlineAnswer:\newline

Full solution

Q. f(x)={5 for x<32 for x=3(x4)2+5 for x>3 f(x)=\left\{\begin{array}{lll} -5 & \text { for } & x<3 \\ 2 & \text { for } & x=3 \\ -(x-4)^{2}+5 & \text { for } & x>3 \end{array}\right. \newlineFind f(2) f(2) \newlineAnswer:\newline
  1. Identify xx value: Since we are looking for f(2)f(2), we need to determine which piece of the piecewise function applies when x=2x = 2.
  2. Determine applicable piece: The function f(x)f(x) is defined as 5-5 for x < 3. Since 22 is less than 33, we use the first piece of the function, which is f(x)=5f(x) = -5.
  3. Calculate f(2)f(2): Therefore, f(2)=5f(2) = -5.

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