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f(t)=100(1.1)^(3t)
Which of the following is an equivalent form of the function 
f in which the exponent is 
t ?
Choose 1 answer:
(A) 
f(t)=100(1.331)^(t)
(B) 
f(t)=100(3.3)^(t)
(C) 
f(t)=100(4.1)^(t)
(D) 
f(t)=300(1.1)^(t)

f(t)=100(1.1)3tf(t)=100(1.1)^{3t}\newlineWhich of the following is an equivalent form of the function ff in which the exponent is tt?\newlineChoose 11 answer:\newline(A) f(t)=100(1.331)tf(t)=100(1.331)^{t}\newline(B) f(t)=100(3.3)tf(t)=100(3.3)^{t}\newline(C) f(t)=100(4.1)tf(t)=100(4.1)^{t}\newline(D) f(t)=300(1.1)tf(t)=300(1.1)^{t}

Full solution

Q. f(t)=100(1.1)3tf(t)=100(1.1)^{3t}\newlineWhich of the following is an equivalent form of the function ff in which the exponent is tt?\newlineChoose 11 answer:\newline(A) f(t)=100(1.331)tf(t)=100(1.331)^{t}\newline(B) f(t)=100(3.3)tf(t)=100(3.3)^{t}\newline(C) f(t)=100(4.1)tf(t)=100(4.1)^{t}\newline(D) f(t)=300(1.1)tf(t)=300(1.1)^{t}
  1. Given function transformation: We are given the function f(t)=100(1.1)3tf(t) = 100(1.1)^{3t} and we need to express it in a form where the exponent is just tt. To do this, we need to find a base that raised to the power of tt will give us the same result as (1.1)3t(1.1)^{3t}.
  2. Find equivalent base: To find the equivalent base for the exponent tt, we can raise 1.11.1 to the power of 33 and then use that result as the new base. This is because (1.1)3t(1.1)^{3t} is the same as (1.13)t(1.1^3)^t.
  3. Calculate new base: Now we calculate 1.131.1^3 to find the new base.\newline1.13=1.1×1.1×1.11.1^3 = 1.1 \times 1.1 \times 1.1\newline1.13=1.3311.1^3 = 1.331
  4. Rewrite function with new base: Now we can rewrite the function f(t)f(t) using the new base we found: f(t)=100(1.331)tf(t) = 100(1.331)^t This is the equivalent form of the function with the exponent as tt.
  5. Match with answer choices: Looking at the answer choices, we see that option (A) matches our calculation:\newline(A) f(t)=100(1.331)tf(t) = 100(1.331)^t

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