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f(n)=93+4(n-1)
Complete the recursive formula of 
f(n).

{:[f(1)=◻],[f(n)=f(n-1)+]:}

f(n)=93+4(n1) f(n)=93+4(n-1) \newlineComplete the recursive formula of f(n) f(n) .\newlinef(1)=f(n)=f(n1)+ \begin{array}{l} f(1)=\square \\ f(n)=f(n-1)+ \end{array}

Full solution

Q. f(n)=93+4(n1) f(n)=93+4(n-1) \newlineComplete the recursive formula of f(n) f(n) .\newlinef(1)=f(n)=f(n1)+ \begin{array}{l} f(1)=\square \\ f(n)=f(n-1)+ \end{array}
  1. Identify First Term: Identify the first term of the sequence using the explicit formula f(n)=93+4(n1)f(n)=93+4(n-1) by substituting n=1n=1.\newlineCalculation: f(1)=93+4(11)=93+4(0)=93+0=93f(1) = 93 + 4(1-1) = 93 + 4(0) = 93 + 0 = 93.
  2. Recognize Arithmetic Sequence: Recognize that the sequence defined by f(n)=93+4(n1)f(n)=93+4(n-1) is arithmetic, with a common difference found by evaluating the coefficient of nn in the explicit formula.\newlineCalculation: The common difference is 44, as it is the coefficient of (n1)(n-1).
  3. Write Recursive Formula: Write the recursive formula using the first term and the common difference. The recursive formula has the form f(n)=f(n1)+df(n) = f(n-1) + d, where dd is the common difference.\newlineCalculation: Since f(1)=93f(1) = 93 and the common difference d=4d = 4, the recursive formula is f(n)=f(n1)+4f(n) = f(n-1) + 4.

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