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f(n)=-11+22(n-1)
Complete the recursive formula of 
f(n).

{:[f(1)=◻],[f(n)=f(n-1)+]:}

f(n)=11+22(n1) f(n)=-11+22(n-1) \newlineComplete the recursive formula of f(n) f(n) .\newlinef(1)=f(n)=f(n1)+ \begin{array}{l} f(1)=\square \\ f(n)=f(n-1)+ \end{array}

Full solution

Q. f(n)=11+22(n1) f(n)=-11+22(n-1) \newlineComplete the recursive formula of f(n) f(n) .\newlinef(1)=f(n)=f(n1)+ \begin{array}{l} f(1)=\square \\ f(n)=f(n-1)+ \end{array}
  1. Identify First Term: Identify the first term of the sequence using the given explicit formula. The explicit formula is f(n)=11+22(n1)f(n)=-11+22(n-1). To find the first term, f(1)f(1), we substitute n=1n=1 into the formula.\newlinef(1)=11+22(11)=11+22(0)=11+0=11f(1) = -11 + 22(1-1) = -11 + 22(0) = -11 + 0 = -11.
  2. Determine Common Difference: Determine the common difference of the sequence. Since the coefficient of nn in the explicit formula is 2222, this indicates that the common difference, dd, is 2222. This is because each subsequent term increases by 2222 from the previous term.
  3. Write Recursive Formula: Write the recursive formula using the first term and the common difference. The recursive formula for an arithmetic sequence is given by:\newlinef(n)=f(n1)+df(n) = f(n-1) + d, where dd is the common difference.\newlineSince we have already determined that f(1)=11f(1) = -11 and d=22d = 22, we can write the recursive formula as:\newlinef(n)=f(n1)+22f(n) = f(n-1) + 22.

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