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F=(K-273.15)*1.8+32.00
An equation for temperature conversion from 
K degrees Kelvin to 
F degrees Fahrenheit is given by the equation. What is the significance of 273.15 in the equation?
Choose 1 answer:
(A) A temperature of 273.15 Kelvin degrees converts to 0 Fahrenheit degrees.
(B) A temperature of -273.15 Kelvin degrees converts to 0 Fahrenheit degrees.
(C) A temperature of 273.15 Kelvin degrees converts to 32 Fahrenheit degrees.
(D) A temperature of -273.15 Kelvin degrees converts to 32 Fahrenheit degrees.

F=(K273.15)1.8+32.00 F=(K-273.15) \cdot 1.8+32.00 \newlineAn equation for temperature conversion from K K degrees Kelvin to F F degrees Fahrenheit is given by the equation. What is the significance of 273273.1515 in the equation?\newlineChoose 11 answer:\newline(A) A temperature of 273273.1515 Kelvin degrees converts to 00 Fahrenheit degrees.\newline(B) A temperature of 273-273.1515 Kelvin degrees converts to 00 Fahrenheit degrees.\newline(C) A temperature of 273273.1515 Kelvin degrees converts to 3232 Fahrenheit degrees.\newline(D) A temperature of 273-273.1515 Kelvin degrees converts to 3232 Fahrenheit degrees.

Full solution

Q. F=(K273.15)1.8+32.00 F=(K-273.15) \cdot 1.8+32.00 \newlineAn equation for temperature conversion from K K degrees Kelvin to F F degrees Fahrenheit is given by the equation. What is the significance of 273273.1515 in the equation?\newlineChoose 11 answer:\newline(A) A temperature of 273273.1515 Kelvin degrees converts to 00 Fahrenheit degrees.\newline(B) A temperature of 273-273.1515 Kelvin degrees converts to 00 Fahrenheit degrees.\newline(C) A temperature of 273273.1515 Kelvin degrees converts to 3232 Fahrenheit degrees.\newline(D) A temperature of 273-273.1515 Kelvin degrees converts to 3232 Fahrenheit degrees.
  1. Substitute and Calculate: To understand the significance of 273.15273.15 in the equation, let's substitute KK with 273.15273.15 and calculate FF. \newlineF=(273.15273.15)×1.8+32F = (273.15 - 273.15) \times 1.8 + 32 \newlineF=(0)×1.8+32F = (0) \times 1.8 + 32 \newlineF=0+32F = 0 + 32 \newlineF=32F = 32
  2. Check Options: Now, let's check the options to see which one matches our calculation.\newline(A) Incorrect, because 273.15273.15 Kelvin does not convert to 00 Fahrenheit.\newline(B) Incorrect, because 273.15-273.15 Kelvin is not a valid temperature as Kelvin cannot be negative.\newline(C) Correct, because our calculation shows that 273.15273.15 Kelvin converts to 3232 Fahrenheit.\newline(D) Incorrect, because 273.15-273.15 Kelvin is not a valid temperature, and our calculation did not result in 3232 Fahrenheit for 273.15-273.15 Kelvin.

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