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Express the given expression without logs, in simplest form. Assume all variables represent positive values.

(3^(-3log_(3)4x^(2)))
Answer:

Express the given expression without logs, in simplest form. Assume all variables represent positive values.\newline(33log34x2) \left(3^{-3 \log _{3} 4 x^{2}}\right) \newlineAnswer:

Full solution

Q. Express the given expression without logs, in simplest form. Assume all variables represent positive values.\newline(33log34x2) \left(3^{-3 \log _{3} 4 x^{2}}\right) \newlineAnswer:
  1. Understand and Apply Power Rule: Understand the given expression and apply the power rule of logarithms.\newlineThe expression is 33log34x23^{-3\log_{3}4x^{2}}. According to the power rule of logarithms, aloga(b)=ba^{\log_{a}(b)} = b. We will use this rule to simplify the expression.
  2. Apply Power Rule to Logarithmic Part: Apply the power rule to the logarithmic part of the expression.\newlineThe power rule states that a(nloga(b))=bna^{(n\log_a(b))} = b^n. Here, a=3a = 3, n=3n = -3, and loga(b)=log34x2\log_a(b) = \log_{3}4x^{2}. So we can rewrite the expression as (4x2)3(4x^{2})^{-3}.
  3. Simplify Using Power of a Power Rule: Simplify the expression using the power of a power rule.\newlineThe power of a power rule states that (bn)m=bnm(b^n)^m = b^{n*m}. Applying this rule, we get 43×(x2)34^{-3} \times (x^{2})^{-3}.
  4. Calculate Powers to Simplify: Simplify the expression further by calculating the powers. 43=143=1644^{-3} = \frac{1}{4^3} = \frac{1}{64} and (x2)3=1(x23)=1x6(x^{2})^{-3} = \frac{1}{(x^{2*3})} = \frac{1}{x^6}. So the expression becomes 1641x6.\frac{1}{64} * \frac{1}{x^6}.
  5. Combine Fractions for Final Expression: Combine the fractions to get the final simplified expression.\newlineMultiplying the fractions, we get 164x6\frac{1}{64x^6}.

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