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Express the following fraction in simplest form, only using positive exponents.

((-4y^(4))^(2))/(-5y^(3))
Answer:

Express the following fraction in simplest form, only using positive exponents.\newline(4y4)25y3 \frac{\left(-4 y^{4}\right)^{2}}{-5 y^{3}} \newlineAnswer:

Full solution

Q. Express the following fraction in simplest form, only using positive exponents.\newline(4y4)25y3 \frac{\left(-4 y^{4}\right)^{2}}{-5 y^{3}} \newlineAnswer:
  1. Identify Base and Exponents: Write down the given expression and identify the base and exponents.\newlineThe given expression is ((4y4)2)/(5y3)((-4y^{4})^{2})/(-5y^{3}).\newlineHere, we have a power to a power for the numerator, which means we will multiply the exponents, and a negative base for the denominator.
  2. Apply Power to Power Rule: Apply the power to a power rule to the numerator.\newline((4y4)2)=(4)2×(y4)2((-4y^{4})^{2}) = (-4)^{2} \times (y^{4})^{2}\newlineAccording to the power to a power rule, (am)n=am×n(a^{m})^{n} = a^{m\times n}.\newlineSo, we have (4)2×y4×2=16×y8(-4)^{2} \times y^{4\times 2} = 16 \times y^{8}.
  3. Simplify Denominator: Simplify the denominator.\newlineThe denominator is 5y3-5y^{3}. Since we want only positive exponents, we leave the denominator as it is because the exponent on yy is already positive.
  4. Combine Numerator and Denominator: Combine the simplified numerator and denominator.\newlineNow we have 16×y816 \times y^{8} for the numerator and 5y3-5y^{3} for the denominator.\newlineSo, the expression becomes (16×y8)/(5y3)(16 \times y^{8}) / (-5y^{3}).
  5. Divide Coefficients and Subtract Exponents: Divide the coefficients and subtract the exponents of like bases.\newlineDivide 1616 by 5-5 to get 165-\frac{16}{5}.\newlineSubtract the exponents of yy: y(83)=y5y^{(8-3)} = y^{5}.\newlineThe expression now is (165)y5(-\frac{16}{5})y^{5}.
  6. Write Final Simplified Expression: Write the final simplified expression.\newlineThe final simplified expression is 165y5\frac{-16}{5}y^{5}.

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