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Express the following fraction in simplest form, only using positive exponents.

((-5w^(-5))^(2))/(-5w^(-2))
Answer:

Express the following fraction in simplest form, only using positive exponents.\newline(5w5)25w2 \frac{\left(-5 w^{-5}\right)^{2}}{-5 w^{-2}} \newlineAnswer:

Full solution

Q. Express the following fraction in simplest form, only using positive exponents.\newline(5w5)25w2 \frac{\left(-5 w^{-5}\right)^{2}}{-5 w^{-2}} \newlineAnswer:
  1. Apply Power to Numerator: Apply the power to the numerator.\newlineWhen raising a power to a power, you multiply the exponents. In this case, we have (5w5)2(-5w^{-5})^2, which means we need to square both 5-5 and w5w^{-5}.\newline((5)2(w5)2)=(25w10)((-5)^2 \cdot (w^{-5})^2) = (25 \cdot w^{-10})
  2. Rewrite Denominator with Positive Exponents: Rewrite the denominator with positive exponents.\newlineTo convert a negative exponent to a positive exponent, you take the reciprocal of the base. So, 5w2-5w^{-2} becomes 5w2-\frac{5}{w^2}.
  3. Combine Numerator and Denominator: Combine the numerator and denominator.\newlineNow we have (25w10)/(5/w2)(25 \cdot w^{-10}) / (-5/w^2). To divide by a fraction, you multiply by its reciprocal. So, we multiply 25w1025 \cdot w^{-10} by w2/5w^2/-5.\newline(25w10)(w2/5)(25 \cdot w^{-10}) \cdot (w^2/-5)
  4. Simplify the Expression: Simplify the expression.\newlineWe can cancel out the 5-5 in the numerator and denominator and multiply the ww terms by adding the exponents.\newline(25/5)×(w(10)×w2)=5×w(10+2)=5×w(8)(25/-5) \times (w^{(-10)} \times w^2) = -5 \times w^{(-10+2)} = -5 \times w^{(-8)}
  5. Rewrite with Positive Exponents: Rewrite the expression with positive exponents.\newlineTo make the exponent of ww positive, we take the reciprocal of w8w^{-8}, which gives us w8w^8 in the denominator.\newline5w8-\frac{5}{w^8}

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