Q. Express the following fraction in simplest form, only using positive exponents.4k7v5(3k3v2)−5Answer:
Apply negative exponent rule: Apply the negative exponent rule to the numerator.The negative exponent rule states that a−n=an1. We will apply this rule to the numerator to make the exponent positive.((3k3v2)−5)=((3k3v2)5)1
Expand numerator exponent: Expand the exponent in the numerator.When raising a power to a power, you multiply the exponents. We will apply this to each factor in the numerator.(3k3v2)51=35⋅(k3)5⋅(v2)51
Calculate powers in numerator: Calculate the powers in the numerator.Now we will calculate each of the powers separately.35×(k3)5×(v2)51=243×k15×v101
Combine numerator and denominator: Combine the numerator and the denominator.Now we will write the entire fraction with the expanded numerator and the original denominator.243⋅k15⋅v101/14k7v5
Simplify fraction by dividing: Simplify the fraction by dividing the numerator by the denominator.To divide two fractions, you multiply the first fraction by the reciprocal of the second fraction.243⋅k15⋅v101⋅4k7v51
Multiply the fractions: Multiply the fractions.Now we will multiply the numerators and the denominators separately.(1×1)/(243×k15×v10×4k7×v5)
Combine like terms in denominator: Combine like terms in the denominator.We will add the exponents of like bases in the denominator.(243×4×k15+7×v10+5)1
Calculate exponents and coefficients: Calculate the exponents and coefficients in the denominator.Now we will calculate the exponents and multiply the coefficients.972×k22×v151
Write final answer: Write the final answer with positive exponents.The fraction is already in simplest form with positive exponents.972⋅k22⋅v151
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