Express as a function of a DIFFERENT angle, 0^(@) <= theta < 360^(@). cos(154^(@)) cos(◻^(@))

Find Reference Angle: We need to express cos(154°) in terms of a reference angle. A reference angle is the acute angle formed by the terminal side of an angle and the x-axis. The reference angle for any angle in the second quadrant, where 154° lies, is found by subtracting the angle from 180°. Calculation: 180° - 154° = 26°Use Even Property: The cosine function is even, which means that cos(θ) = cos(-θ). Therefore, cos(154°) can be expressed as cos(180° - 26°), which is equivalent to -cos(26°) because cosine is negative in the second quadrant.Express as -cos(26°): We have now expressed cos(154°) as a function of a different angle, -cos(26°), which is within the range 0° ≤ θ < 360°.

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Express as a function of a DIFFERENT angle,
0^(@) <= theta < 360^(@).

cos(154^(@))

cos(◻^(@))

Express as a function of a DIFFERENT angle, 0^{\circ} \leq \theta<360^{\circ} . $\newline$ $\cos \left(154^{\circ}\right)$ $\newline$ $\cos \left(\square^{\circ}\right)$

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Algebra 2

Find trigonometric ratios using reference angles

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Q. Express as a function of a DIFFERENT angle,

0^{\circ} \leq \theta<360^{\circ}

\newline

\cos \left(154^{\circ}\right)

\newline

\cos \left(\square^{\circ}\right)

Find Reference Angle: We need to express $\cos(154°)$ in terms of a reference angle. A reference angle is the acute angle formed by the terminal side of an angle and the x-axis. The reference angle for any angle in the second quadrant, where $154°$ lies, is found by subtracting the angle from $180°$ . $\newline$ Calculation: $180° - 154° = 26°$
Use Even Property: The cosine function is even, which means that $\cos(\theta) = \cos(-\theta)$ . Therefore, $\cos(154^\circ)$ can be expressed as $\cos(180^\circ - 26^\circ)$ , which is equivalent to $-\cos(26^\circ)$ because cosine is negative in the second quadrant.
Express as $-\cos(26°)$ : We have now expressed $\cos(154°)$ as a function of a different angle, $-\cos(26°)$ , which is within the range 0° \leq \theta < 360°.